Michaela runs to the end of her street and back in 90 s. Her brother, Jacob, walks to the end of the street and back in 3 min. They both run or walk for the same amount of time, but Michaela makes 5 more trips than Jacob. How many times did each person go to the end of the street and back?

Given :

Michaela runs to the end of her street and back in 90 s.

Her brother, Jacob, walks to the end of the street and back in 3 min.

They both run or walk for the same amount of time, but Michaela makes 5 more trips than Jacob.

To Find :

How many times did each person go to the end of the street and back.

Solution :

Let, they both walk for T seconds.

Number of rounds Michaela walk is, n₁ = T/90 .

Number of rounds Jacob walk is, n₂ =T/180 .

It is given that :

n₁ = n₂ + 5

T/90 + T/180 = 5

( T/90 + T/180 ) × 180 = 5×180

2T + T = 900

3T = 900

T = 300 s

So, n₁ = 300/90 = 3

n₂ = 1

Hence, this is the required solution.

all the angles opposite to the angle 150 would be 150 and all the angles that are next to 150 are 30 because they equal 180 it you add it up.

step-by-step explanation:

94

step-by-step explanation:

average the numbers and use a variable to figure out the minimum to get a 90.

(79+94+91+92+x)/5=90

x = 94