A bridge hand is made up of 13 cards from a deck of 52. Find the probability that a hand chosen at random contains at least .

10%

Step-by-step explanation:

Since the question is not complete, I will be solving for probability of 3 9s

To solve this, we would be using the principle of combination, and thus

A deck of 52 hours has 4 nines, the probability that it contains at least 3 9s is mathematically represented by the equation.

P ( x ≥ 3 ) = ( 48 C 10 · 4 C 3 ) / ( 52 C 13 ) + ( 48 C 9 · 4 C 4 ) / ( 52 C 13 )

Remember I told us were going to be using the principle of combination. Well then

nCr = n!/r!(n - r)!

Now, applying the above stated formula to the equation, we have

48C10 = 48!/10!(38!)

4C3 = 4!/3!(1!)

52C13 = 52!/13!(39!)

48C9 = 48!/9!(39!)

4C4 = 4!/4!(0!)

Solving for each independently, we find that

= 0.0412 + 0.588 = 0.1

unpaid balance is : $149.99-$50 = $99.99 new balance = 149.99+2.62-50 = $102.61 finance charge = 99.99- 0.21/12= $1.75 new balance = 99.99+1.75 = $101.74 average daily balance method average daily balance= 3399.70/30 = $113.32 finance charge = $ 0.21/12ă—113.32 = $1.98 new balance = $149.99-50+1.98 = $101.97