HELP ME WITH THIS ALSO.WILL GIVE BRAINLIEST...

A is (10,0)

B is (3, 3).

Step-by-step explanation:

First we calculate the coordinates of the point A.

Here, y = 0 so we have:

7(0) - 3x + 30 = 0

-3x + 30 = 0

x = -30/-3 = 10.

So A has coordinates (10,0).

Next we find the coordinates of the points where the line passes through the y axis. Here x = 0:

7x - 3(0) = 30

x = 30/7.

So the point is (0, 30/7).

Let the point B have coordinates (x1, y1)  

Now x1 = y1 (given).

If we draw a line from B perpendicular to the x axis ( its length will be = y1) then we have 2 similar triangles.

So  as corresponding sides are in the same ratio:

y1/ (30/7) = (10-x1) / 10  

But as x1 = y1:

x1/ (30/7) = (10-x1) / 10  

7 x1 / 30 = (10-x1) / 10

70 x1 = 30(10 - x1)

70x1 = 300 - 30 x1

100 x1 =  300

x1 = 3

So the coordinates of B are (3,3)

Checking the solution to the equation:

LHS = 3 / 30/7  = 3*7 / 30 = 21/30 = 7/10.

RHS = (10 -3 ) / 10 = 7/10.