The sum of three consecutive even integers is 36 . find the smallest of them

10

Step-by-step explanation:

You can get the three consecutive integers by using algebraic expressions.

Let's solve.

Let x be the smallest even integer.

Let x+2 be the second even integer.

Let x+4 be the largest even integer.

Therefore, 10 is the smallest even integer.

x+2 = 10+2 = 12

The second even integer is 12.

x+4 = 10+4 = 14

The largest even integer is 14.

Let's check by adding the three even integers.

10+12+14 = 36

36 = 36

It's correct.