PLEASE HELP ME TIME SENSITIVE The mean life of a television set is 123 months with a standard deviation of 19 months. If a sample of 55 televisions is randomly selected, what is the probability that the sample mean would differ from the true mean by greater than 1.2 months?

I just need help getting from 1 - P (-0.47 < z < 0.47) to the answer. In my lesson it says the next step is 0.3192 but I have NO CLUE where that number comes from.

1- P(-0.47 < z < 0.47) = 0.63836

Step-by-step explanation:

Here, we want to get the answer to;

1-P ( -0.47 < z < 0.47)

Mathematically, we are going to use the standard normal distribution table for this

Let us try to evaluate;

P(-0.47 < z < 0.47)

Mathematically, that will be;

P (z < 0.47) - P(z < -0.47)

where P (z < -0.47) = P( z > 0.47)

so we have

P(-0.47 < z < 0.47) = P(z < 0.47) - P(z > 0.47)

So we have this using the standard normal distribution table as follows;

0.68082 - 0.31818 = 0.36164

Now, we can insert this in the earlier expression of;

1- P(-0.47 < z < 0.47)

= 1-0.36164 = 0.63836

Please give credit to Adetunmbiadekunle, who wrote this answer and do not mark me brainliest.

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18

do i do it on a graph?

step-by-step explanation: