What is the image of (-12,3)(−12,3) after a dilation by a scale factor of \frac{1}{3} 3 1 centered at the origin?

The image of A(-12, 3) after dilation by a scale factor of 1/3 will be: A'(-4, 1)

Step-by-step explanation:

Given the coordinates of the point

Let suppose the given point is A(-12, 3)

We know that when an object is dilated by a scale factor, it gets reduced, stretched, or remains the same, depending upon the value of the scale factor.

If the scale factor > 1, the image is enlarged

If the scale factor is between 0 and 1, it gets shrunk

If the scale factor = 1, the object and the image are congruent

Rule to calculate the dilation by a scale factor 1/3 centered at the origin

P(x, y) → P'(1/3x, 1/3y)

Here, P'(1/3, 1/3y) is the image of P(x, y).

Thus,

A(-12, 3) → A'(1/3(-12), 1/3(3)) = A'(-4, 1)

Therefore, the image of A(-12, 3) after dilation by a scale factor of 1/3 will be: A'(-4, 1)

step-by-step explanation:

de-gf

hj=3x+20

ji=15x-64