Jack measured a line to be 17.2 inches long. If the actual length of the line is 16.6 inches, then what was the percent error of the measurement, to the nearest tenth of a percent?

3.6%

Step-by-step explanation:

(0.6/16.6)x100=3.61445783133

so rounded to the nearest tenth is 3.6%

The computation of percentage error involves the use of the absolute error, which is simply the difference between the observed and the true value. The absolute error is then divided by the true value, resulting in the relative error, which is multiplied by 100 to obtain the percentage error.

x=half

step-by-step explanation: