Mr. Case is placing boxes along one of the walls in his attic. If the wall is 11 1⁄3 feet long and each box is 2 1/2 feet long, how many boxes can he fit along the

4 8/15 boxes

Step-by-step explanation:

From the above question:

2 1/2 feet = 1 box

11 1/3 feet = x boxes

Cross Multiply

2 1/2 feet × x = 11 1/3 feet × 1 box

x boxes = 11 1/3 /2 1/2

x boxes = 34/3 ÷ 5/2

x = 34/3 ×2/5

x = 68/15

x = 4 8/15 boxes

Hence, he can fit 4 8/15 boxes

this shows a reflection over the x-axis and is translated one unit down and 6 units to the right (x + 6, y - 1)

hope this !

~just a girl in love with shawn mendes

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: