in an examination ,80%examines passed in English ,70%in mathematics and 60% in both subject if 45 examines failed in both find the number of examines who passed only one subject also the number of examines who failed mathematics

135 and 135

Step-by-step explanation:

The computation is shown below:

The number of examiners who passed in only one subject is as follows

=  n(E) - n(E ∩M) + n(M) - n(E ∩M)

= (80 - 60 + 70 - 60)%

= 30%

Now the number of students who passed in minimum one subject is

n(E∪M) = n(E) + n(M) -  n(E ∩M)

= 80 - + 70 - 60

= 90%

Now the number of students who failed in both subjects is

= 100 - 90%

= 10% of total students

= 45

So total number of students appeared for this 450

So, those who passed only one subject is

= 450 × 30%

= 135

Now the Number of students who failed in mathematics is

= 100% - Passed in Mathematics

= 100% - 70%

= 30% of 450

= 135

i did it myself and i got 4.2 (b) hope its right

step-by-step explanation:

the correct answer is x/3+10≥32

hope this !