A polynomial function has a root of -6 with multiplicity 1, a root of -2 with multiplicity 3, a root of 0 with multiplicity 2 and a root of 4 with multiplicity 3. If the function has a positive leading coefficient and is of odd degree, which statement about the graph is true? The graph of the function is positive on (-6, -2). The graph of the function is negative on (-∞, 0). The graph of the function is positive on (-2, 4). The graph of the function is negative on (4,∞)

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  (a)  The graph of the function is positive on (-6, -2)

Step-by-step explanation:

A function of odd degree and positive leading coefficient will be negative from -∞ to the left-most zero. Here, that zero is -6. The multiplicity of that zeros is odd (1), so the sign changes to positive at that point, and remains positive until the next odd-multiplicity zero, which is -2, with multiplicity 3.

Hence the function is positive on the interval (-6, -2), matching choice A.

answer: procent 54 wynosi 33,33%

from the figure we get,

the x axis shows   the months and,

the y-axis shows the number of satisfied customer.

each line or each cell in upward direction (y-axis) shows 500.

the appropriate scale for the y - axis is: -

a = 2000 customers

b = 4000 customers

c = 6000 customers

d = 8000 customers

e = 10000 customers

f = 12000 customers

g = 14000 customers