Write an equation of the line that passes through (2,0) and is perpendicular to the line y=-1/7x-3 An equation of the perpendicular line is y=

Step-by-step explanation:

The slope of the given line y=-1/7x-3 is -1/7.  The slope of any 'new' line perpendicular to this given line is the negative reciprocal of the slope of the latter, which in this case is +7.

Use the point-slope formula y - k = m(x - h) with k = 0, h = 2 and m = +7:

y - 0 = 7(x - 2), or

y = 7(x - 2), or

y = 7x - 14

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secant-secant formula:

(whole secant) x (external part) =           (whole secant) x (external part)

(8+y-2) *8=                                           (y+4+6) *6

(y+6)*8 = (y+10) *6

distribute

8y+48 = 6y +60

subtract 6y from each side

2y +48 = 60

subtract 48 from each side

2y = 12

divide by 2

y = 6

sv =     (y+4+6)

sv   = 6+4+6

sv = 16