Determine all possibilities for the solution set of a system of 2 equations in 2 unknowns. I. No solutions whatsoever. II. One and only one solution. III. Many solutions.

II. One and only one solution

Step-by-step explanation:

Determine all possibilities for the solution set of a system of 2 equations in 2 unknowns. I. No solutions whatsoever. II. One and only one solution. III. Many solutions.

Let assume the equation is given as;

x + 3y = 11 1

x - y = -1 2

Using elimination method

Subtract equation 1 from 2

(x-x) + 3y-y = 11-(-1)

0+2y = 11+1

2y = 12

y = 12/2

y = 6

Substitute y = 6 into equation 2:

x-y = -1

x - 6 = -1

x = -1 + 6

x = 5

Hence the solution (x, y) is (5, 6)

Hence we can say the equation has One and only one solution since we have just a value for x and y

add all the numbers and check the ones place.

the answer is 486. as the ones place is more than 4, the estimation will be the next 10 ie, 490

idk the answer but just put a

step-by-step explanation: