Nine voltage measurements in a circuit have produced the following values: 12.09, 12.05, 11.94, 11.99, 12.12, 12.05, 12.02, 11.95, 12.14. If the standard deviation for the above data set is 0.07V, determine whether any values can be rejected. (5 Points)

we can not reject any value

Step-by-step explanation: From data we can test the highest and the lowest value to evaluate if one of these values are out of certain confidence Interval

If we established CI = 95 % then  α = 5 % and  α/2 = 0,025

From data we find the mean of the values

μ₀  = 12,03   and σ = 0,07

From z table we find z score for 0,025 is  z(c) = ± 1,96

So limits of our CI are:

12,03 + 1,96 =  13,99

12,03 - 1,96 = 10,07

And all our values are within  ( 10,07 , 13,99)

So we can not reject any value

step-by-step explanation: you take each of the numbers and divide by the amount then you take the range

2.2°  

step-by-step explanation:

let θ = the angle of elevation.

tanθ =77/2020

tanθ = 0.038 12

      θ = tan⁻¹0.038 12

      θ = 2.2°