I need help with math algebra homework

1. Slope: -3/4

2. Point-slope: y+4=-3/4(x+4)

3. Slope-intercept: y=-3/4x-7

4. Standard form: 3x+4y=-28

Step-by-step explanation:

1. To find the slope, use the slope formula, which is: y2-y1/x2-x1.

Plug the y-coordinates into the top part of the equation and the x-coordinates into the bottom part.

2--4/-4-4

2+4/-8 = 6/-8, or 3/-4

2. Use the slope and one of the x and  y coordinates to put the equation into point-slope form. Recall that point-slope form is: y-y1=m(x-x1). Let's use the coordinates (4,-4).

y+4=-3/4(x+4)

3. To put the point-slope equation into slope-intercept form (y=mx+b), you need to distribute -3/4 to x+4 and subtract 4 from both sides.

When you distribute, the equation becomes:

y+4=-3/4x-3

Finally, when you subtract 4, the equation becomes:

y=-3/4x-7

4. Standard form is written as x+y= #.

To convert y=mx+b to standard form, first subtract -3/4x from both sides.

-3/4x + y = -7

Multiply everything by 4

3x + 4y = -28

i believe that the slope of the line is -5

step-by-step explanation: