Raj wrote the four equations that are shown below. A

3 (x + 4) = 3 (x + 2) + 6
B

6 (x minus 1) = 3 (x minus 1) + 3

C

5 x + 4 minus x = 2 (2 x minus 2)
D

Negative 2 (x + 3) + x = negative x minus 6

He examined them, without solving them, to determine which has no solution. Which of Raj’s equations has no solution?

C 5 x + 4 minus x = 2 (2 x minus 2)

Step-by-step explanation:

first anwser choice.

step-by-step explanation:

the greater/less or equal to symbol (> or < with the line at the bottom) is a closed/filled in circle.

-5c + 2 _< _27

subtract from both sides by 2

-5c _< _ 27

divide both sides by -5

c _< _ 5.4

flip the inequality sign

c _> _5.4

the only possible answer that would match the simplified inequality is the first answer choice

mr. flanders’ class sold 47 doughnuts and   mr. rodriquez’s class sold 38 cartons of milk

step-by-step explanation:

let x be the number of doughnuts sold by mr. flanders’ class and y be the number of cartons sold by mr. rodriquez’s class.

1. together, the classes sold 85 items, then

x+y=85.

2. both classes earn earned $104.49 for their school. if doughnuts were sold for $1.35 each, then x doughnuts costed $1.35x. if cartons of milk were sold for $1.08 each, then y cartons costed $1.08y. hence,

1.35x+1.08y=104.49.

3. solve the system of two equations: