Y ≥ 12x – 1
y < 43x – 2

Step-by-step explanation:

The solution to this problem is a graph.

Graph y ≥ 12x - 1:  this is a straight solid line with slope 12 and y-intercept -1.  Due to the presence of the  ≥  operator, we must shade (darken) the entire area above this line.  

Next, graph y < 43x – 2 using a dashed line (due to the < operator):  The slope is 43 and the y-intercept is -2.

Determine where the two lines intersect, either from the graph or algebraically.  If algebraically:

equate the two givens:

y = 12x - 1 = y = 43x – 2, which simplifies first to:

12x - 1 = 43x - 2, and second to

1 = 43x - 12x = 31x, which results in x = 1/31.

Substituting 1/31 for x in the first equation, we get:

y = 12(1/31) - 1, or y = 12/31 - 1, or y = 12/31 - 31/31, or y = 19/31

The two graphs intersect at (1/31, 19/31)

Shade (darken) the area beneath (under) the dashed line y < 43x – 2.

The solution is the area that you have darkened twice.

answer: i'm not sure

step-by-step explanation:

step-by-step explanation:

the true ones are a b and d