Out of a total of 2,000 boxes, 40% were red. 50% of the red boxes were sold. a. How many red boxes were sold? b. How many boxes were not red in color? plz help and teach me how to mark as brainliest so i can do that to people who help me

400 red boxes were sold

Step-by-step explanation:

Step 1: Our output value is 2000.

Step 2: We represent the unknown value with x.

Step 3: From step 1 above,2000=100%.

Step 4: Similarly, x=40%.

Step 5: This results in a pair of simple equations:

2000=100%

x=40%(2)

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

2000/x = 100%/40%

Step 7: Again, the reciprocal of both sides gives

x/2000 = 40%/100%

x=800

Therefore, 40% of 2000 is 800

and to find 50% just divide by 2

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

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