The slope of the line that passes through points -2,3 and 10,3 is

i gave you the slope and if its a function

Step-by-step explanation:

it a function  

Slope (m) =ΔYΔX=0

θ =arctan(ΔY)ΔX=0°

ΔX = 10 – -2 = 12

ΔY = 3 – 3 = 0

Distance (d) = √ΔX2 + ΔY2 = √144 = 12

Equation of the line:

y = 0x + 3

When x=0, y = 3

m = 1/7

Step-by-step explanation:

Start with the slope formula (m= y2 - y1 / x2 - x1)

Plug y2 with 5, y1 with 6, x2 with 3, and x1 with 10

Subtract 6 from 5 to get 1, and subtract 10 from 3 to get -7

Simplify the answer to 1/7

So the slope is m= 1/7

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this