Mose decides to launch a rocket out of the barn at Schrute farms. The equation below represents the height (in meters), of the rocket getting launched above the ground, t seconds after the rocket is launched. h(t) = -.4 (t - 2)^2 + 5 How high above the ground is the rocket before it is launched?

Height at an instance of time is given by :

h(t) = -4( t - 2 )² + 5     .....1

Differentiating above equation with respect to t .

Now, for maximum , .

8( t - 2 ) = 0

t = 2

Putting value of t = 2 in given equation, we get :

h( 2 ) = -4( 2 - 2 )² + 5

h( 2 ) = 5 m

Therefore, maximum height rocket can reach is 5 m.

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18

answer: the answer is e

step-by-step explanation: