HELP. Write the equation in slope-intercept form of the line that passes through the given point and has the given slope.
(4, -7); m = -1/4
a. y = -1/4x - 6
b. y = -1/4x - 8
c. y = -1/4x + 6
d. y = -1/ 4x + 8

a. y = -1/4x - 6

Step-by-step explanation:

slope intercept formula is y = mx + b with m being the slope, b being the y-intercept, and y and x being any point on the line

so plug in the slope and coordinates to solve for b

-7 = (-1/4) × 4 + b

solve for b by simplifying

b = -6

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

3.how is solving radical equations different than solving linear equations?

step-by-step explanation: