If you are able to answer this I’ll give most and I need it in about 20 min Nov
Month June July Aug Sept Oct
Rainfall (in.) 6.14 7.19
8.63
8.38 6.47
2.43
2. The table shows monthly rainfall in inches for
five months. Identify the outlier in the data set.
Determine how the outlier affects the mean,
median, and mode of the data. Then tell which
measure of center best describes the data with
and without the outlier. Round to the nearest
hundredth. Justify your selection.

okay, first to figure out the IQR of the table you need to organize them from least to greatest.

2.43, 6.14, 6.47, 7.19, 8.38, 8.63

to find the middle number of all of these you add them all together and divide by 6, which is the total amount of numbers there.

2.43 + 6.14 + 6.47 + 7.19 + 8.38 + 8.63 = 39.24

39.24 / 6 = 6.54

now that we have the IQR, next we find the outlier. to find the outlier you multiply the IQR by 1.5 which is 6.54 x 1.5 = 9.81 <- outlier

Outliers affect the mean value of the data but have little effect on the median or mode of a given set of data.

2.43 + 6.14 + 6.47 + 7.19 + 8.38 + 8.63 + 9.81 = 49.05

49.05 / 7 = 7.00 (Rounded)

I tried my best to solve this, sorry if it doesn't help.

a. is correct