A ball is thrown into the air from height 1.6 m above the ground. It initially gains height at 16.4 ms-1. After 2 seconds, it is falling at 3.2 ms-1. The height of the ball over time can be
modelled by the quadratic function h(t) = at+ bt+c metres, where t is the time in seconds.
a State h(0) and hence find c.
b State h'(0) and hence find b.
c Use the remaining information to find a.
d What was the maximum height reached by the ball, and when did it reach this height?

answer4 to the second power is 16

and 4 to the third power is 64,

the answer is 6

hope this !

secant-secant formula:

(whole secant) x (external part) =           (whole secant) x (external part)

(8+y-2) *8=                                           (y+4+6) *6

(y+6)*8 = (y+10) *6

distribute

8y+48 = 6y +60

subtract 6y from each side

2y +48 = 60

subtract 48 from each side

2y = 12

divide by 2

y = 6

sv =     (y+4+6)

sv   = 6+4+6

sv = 16

32500

step-by-step explanation:

3.25*10000