Use the slope-intercept form to graph the equation y=-8/3x+3

See below :)

Step-by-step explanation:

The easiest way to graph this is to find the x-intercept and y-intercept,

y-intercept:

The y-intercept is extremely easy to find as it's just the "b" in "y = mx + b"

If there is no b, it's (0,0). If there is a b, its (0,b)

This is because the y-intercept is where the lines hits the y-axis so we know x must be 0. We can plug in x as 0 to find y:

y = m(0) + b

y = b

In this case, the y-intercept is (0,3) because the b in y = -8/3x + 3

x-intercept:

The x-intercept requires a little more work. It's the same as the y-intercept. The x-intercept is where the lines hits the x-axis so we know y must be 0. The x-intercept is (x,0)

We can use this to plug in y as 0:

0 = mx + b

mx = -b

Now we use this to find the the x-intercept:

0 = -8/3x + 3

8/3x = 3

Divide both sides by 8/3:

x = 3 * 3/8

x = 9/8

In this case, the x-intercept is (9/8,0)

Now we can use these points and connect a line to them and then the lines keeps going forever. Look at the picture I uploaded :)

4400

step-by-step explanation: