Two bottle rockets are simultaneously launched on parallel paths, from 5 feet apart on level ground. After 0.1 second, the rockets are at the same height. Which theorem or definition can you use to show that the rockets are still 5 feet apart 0.1 second after launch?

Help asap please it's due today :)

The definition of parallel lines are lines that have a constant minimum distance between them at any given point along the lines, such that the lines are the same distance apart all through

Therefore, given that we have;

1) The path of the two bottle rockets are parallel,

2) The initial distance between the two rocket on level ground = 5 feet = The perpendicular (shortest) distance between the two rockets

3) The shortest distance between the rockets having the same height moving on parallel path will be constant = 5 feet

4) The height of the two rockets after 0.1 second = Constant = 5 feet

5) Therefore, by the definition of parallel lines, distance between the two rockets which are at the same height after 0.1 second will still be 5 feet

Step-by-step explanation:

its ok i have one too and i also have big lips

step-by-step explanation:

the solution of the equation is 2.23 ⇒ answer b

step-by-step explanation:

* lets revise the meaning of exponential function

- the form of the exponential function is y = ab^x, where a ≠ 0, b > 0 ,  

  b ≠ 1, and x is any real number

- it has a constant base b

- it has a variable exponent x

- to solve an exponential equation, take the log or ln of both sides,  

  and solve for the variable

* lets solve the problem

∵

- the base is 7 and the exponent is x

- insert ㏑ in both sides

∴

- use the rule

∴ x ㏑(7) = ㏑(77)

- to find x divide both sides by ㏑(7)

∴

* the solution of the equation is 2.23 to the nearest 2 decimal places