Allie fires a rocket from ground level. The height of the rocket is given by the formula h= 260t - 16t^2 (-16t squared), where t is the time in seconds after launch. How long will the rocket be in the air?

The rocket would be in the air for 8.125 seconds after launch.

Step-by-step explanation:

Given that the height of the rocket, h = 260t - 16.

To determine how long the rocket would be in the air, differentiate h totally with respect to t.

So that, total derivative of h is given as;

=

0 = 260 - 16 x 2t

  = 260 - 32t

0 = 260 - 32t

32t = 260

t =

 = 8.125

t= 8.125 seconds

The rocket would be in the air for 8.125 seconds after launch.

rectangle: 9 1/8 x 4 1/9 = 37 37/72in

parallelogram: b times h= 10.3 x 6.2 = 63.86

trapezoid: a+b/2 times h= 42.5

volume of prism: l times w times h= 36

answer: h

step-by-step explanation: