Find the area and perimeter of the square using formula and the given dimensions.
A square with a side length of 13 meters.

A P = 22 m, A = 129 sq. m

B P = 42 m, A = 159 sq. m

C P = 52 m, A = 169 sq. m

D P = 32 m, A = 189 sq. m

A= l×l

= 13×13

A= 169

P= 4l

= 4×13

= 52

so the answer is C

took the test it's 94

explanation:

previous steps have made pa≅ pb ≅ st ≅ su. setting the compass width to ab allows you to make tu the same length. then δstu ≅ δpab by the sss congruence postulate, and ∠p ≅ ∠s by the reason cpctc.