A. Yesterday, Kelly went to the Sea Animal Park on a class trip. The Sea Animal Park had a total of 3,840 visitors for the first 3 weeks of the month. There were 1,368 visitors the first week and 1,277 visitors the second week. What was the number of visitors for the third week? Show your work. B. During the first 3 weeks, 18 buses full of stừdents visited the Sea Animal Park. Each bus had 54 students. What is the total number of students that visited the Sea Animal Park during the 3 weeks? Explain how you found your answer.

C. Yesterday, on Kelly's class trip, 4 groups of 52 students visited the Sea Animal Park. The students attended a special dolphin show in which they were able to pet the dolphins. The students were placed in groups, with 7 students in each group. Kelly used division to find the total number of groups that were needed so that each student was able to pet the dolphins. She said that a total of 29 groups were needed. Did Kelly correctly solve the division problem? Why or why not?

Plzzz answer both questions and i will give you 100 points

Which expression represents the total perimeter of her sandwich, and if x = 1.2, what is the approximate length of the crust?

When booking personal travel by air, one is always interested in actually arriving at one’s final destination even if that arrival is a bit late. the key variables we can typically try to control are the number of flight connections we have to make in route, and the amount of layover time we allow in those airports whenever we must make a connection. the key variables we have less control over are whether any particular flight will arrive at its destination late and, if late, how many minutes late it will be. for this assignment, the following necessarily-simplified assumptions describe our system of interest: the number of connections in route is a random variable with a poisson distribution, with an expected value of 1. the number of minutes of layover time allowed for each connection is based on a random variable with a poisson distribution (expected value 2) such that the allowed layover time is 15*(x+1). the probability that any particular flight segment will arrive late is a binomial distribution, with the probability of being late of 50%. if a flight arrives late, the number of minutes it is late is based on a random variable with an exponential distribution (lamda = .45) such that the minutes late (always rounded up to 10-minute values) is 10*(x+1). what is the probability of arriving at one’s final destination without having missed a connection? use excel.