If the solution of p(x) = 0 are -14 and 11, which function could be p?

step-by-step explanation:

0

the first one is x^2+2x+2

the second one is x^2+4

the last one is x^2-4x+8

"standard form:

3x2 + 14x − 10 = 0

solutions based on quadratic formula:

x1   = −14 − √ 142 − 4×3×(−10) /   2×3   = −14 − 2 × √ 79 /   6   ≈ −5.296

x2   = −14 + √ 142 − 4×3×(−10) /   2×3   = −14 + 2 × √ 79 /   6   ≈ 0.629