subject
Mathematics, 15.12.2020 18:00 jayy6863

In a recent school newspaper survey, 3,000 randomly selected teenagers were asked to cite their primary transportation method to school. Fifteen of 20 teenagers said
they use their own car to get to school. A 90% confidence interval to estimate the
true proportion of teenagers who drive their own car to school is found to be
(0.5907, 0.9093). Which of the following is a correct interpretation of the confidence
level?
Ninety percent of the time, the procedure used to generate this interval will
capture the true proportion of teenagers who drive their own car to school.
Ninety percent of all samples of this size would yield a confidence interval of
(0.5907, 0.9093).
There is a 90% chance that the true proportion of teenagers who drive their
own car to school will be (0.5907, 0.9093).
Ninety percent of all the samples of size 3,000 lie in the confidence interval
(0.5907, 0.9093).
There is a 90% chance that randomly selected teenagers will be part of the 75%
who drive their own car to school.

ansver
Answers: 3

Another question on Mathematics

question
Mathematics, 21.06.2019 21:30
Are the corresponding angles congruent? explain why or why not.
Answers: 2
question
Mathematics, 21.06.2019 21:40
The sides of a parallelogram are 24cm and 16cm. the distance between the 24cm sides is 8 cm. find the distance between the 16cm sides
Answers: 3
question
Mathematics, 21.06.2019 22:30
Math question.. plz me .. best answer all
Answers: 3
question
Mathematics, 22.06.2019 04:50
Q.1 dr. frank needs to choose 3 students from her advanced biology course to attend a conference in hawaii. the course has 40 students. which of the following methods could dr. frank use to choose a simple, random sample of 3 students? select all that apply. 1 dr. frank could have the students line up from shortest to tallest, then use her birthdate, 2/5/39, to select 3 students from the line (the 2nd student, the 5th student, and the 39th student). 2. dr. frank could upload her class roster into a spreadsheet and use a ranom-number generating function to produce 3 random numbers. the students whose names are located in the rows with these 3 numbers on the spreadsheet would be chosen. 3. dr. frank could choose the students with the 3 highest grades in the class. 4. dr. frank could count to three, then the first students to come to the front of the classroom and grab a golden ticket from her hand would be selected. 5. dr. frank could ask all students to write their name on a card, place all of the cards in a hat, shake the hat, and then pull 3 cards out from the hat. the students whose names appear on those 3 cards will be selected. 6. dr. frank could ask for volunteers to go to the conference, then choose the first 3 students who raise their hands. q2. now, choose one of the methods that you did not select and explain why this method would not result in a simple, random sample:
Answers: 2
You know the right answer?
In a recent school newspaper survey, 3,000 randomly selected teenagers were asked to cite their pri...
Questions
question
Mathematics, 05.03.2020 06:34
Questions on the website: 13722361