Ireally need i only have 20 minutes left

a collection of nickels and dimes is worth $2.95. there are 47 coins in all. how many nickels are there?
a.12b.18c.29 d.35

N+d=47
5n+10d=295
divide 2nd by 5

n+2d=59

we have
n+d=47
n+2d=59
eliminate n
multiply first equaton by -1 and add to other equaton
-n-d=-47
n+2d=59 +
0n+1d=12

d=12
sub back

n+d=47
n+12=47
minus 12 both sides
n=35

35 nickles

D is answer