A model for a company’s revenue from selling a software package is R(p)=-2.5p^2+600p

Complete question is;

A model for a company's revenue from selling a software package is R = -2.5p² + 500p, where p is the price in dollars of the software. What price will maximize revenue? Find the maximum revenue.

Price to maximize revenue = $100

Maximum revenue = $25000

Step-by-step explanation:

We are told that:

R = -2.5p² + 500p, where p is the price in dollars of the software.

The maximum revenue will occur at the vertex of the parabola.

Thus, the price at this vertex is;

p = -b/2a

Where a = - 2.5 and b = 500

Thus:

p = -500/(2 × -2.5)

p = -500/-5

p = 100 in dollars

Maximum revenue at this price is;

R(100) = -2.5(100)² + 500(100)

R(100) = -25000 + 50000

R(100) = $25000

450 is the final answer! : )

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.