In 2005 the population of a district was 35.700 with a continuous annual growth rate of approximately 4%, what will the population be in 2030 according to the exponential growth function? Round the answer to the nearest whole numberdo not include the unit in your answer.

Amount in 2030 is $95,169

Given that:

Amount invested = $35,700

Growth rate = 4% = 0.04

Time invested = 2030 - 2005

Time invested = 25 year

Find:

Amount in 2030

Computation:

A = P[1+r]ⁿ

Amount in 2030 = 35700[1+0.04]²⁵

Amount in 2030 = 35700[1.04]²⁵

Amount in 2030 = 35700[2.6658]

Amount in 2030 = $95,169

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Given:

Population is 2005 = 35,700

growth rate = 4% = 0.04

To find:

The population in 2030.

Solution:

The general exponential growth model is

where, a is initial value, r is growth rate and t is time in years.

Let the initial year is 2005. So, number of years between 2005 to 2030 is

Putting a=35,700, r=0.04 and t=25 in the above model.

Approximate the value to the nearest whole number.

Therefore, population of the district will be about 95,170.

the answer is d

the answer is in the first quadrant, which make the y-int positive.

since the dots are going down, therefore the correlation is negative

i hope it is right.