Two savings accounts earn simple interest. Account A has a beginning balance of $500 and grows by $25 per year. Account B has a beginning balance of $750 and grows by $15 per year.

After 25 years both the accounts will have the same balance.

Step-by-step explanation:

Let t years, both the account will have the same balance.

As account A has a beginning balance of $500 and grows by $25 per year.

So, the total balance of account A after t years = 500+25t

Similarly, account B has a beginning balance of $750 and grows by $15 per year.

So, the total balance of account A after t years = 750+15t

As both the accounts has the same balance, so

500+25t= 750+15t

25t-15t=750-500

10t=250

t=250/10

t=25 years

Hence, after 25 years both the accounts will have the same balance.

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18

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step-by-step explanation:

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