two percent of a product are defective. if a lot of 100 items are ordered what's the probability that there are no defective item? what's the probability that there are at least two defective items?

P(X ≥ 2) = 0.5967

Step-by-step explanation:

Using binomial probability distribution formula;

P(X = k) = C(n, k) × p^(k) × (1 - p)^(n - k)

two percent of a product are defective. Thus; p = 0.02

a lot of 100 items are ordered. Thus, n = 100

Probability that there are no defective items is;

P(X = 0) = C(100, 0) × 0.02^(0) × (1 - 0.02)^(100 - 0)

P(X = 0) = 0.98^(100) = 0.1326

the probability that there are at least two defective items will be;

P(X ≥ 2) = 1 - P(X < 2)

Now,

P(X < 2) = P(X = 0) + P(X = 1)

P(X = 1) = C(100, 1) × 0.02^(1) × (1 - 0.02)^(100 - 1)

P(X = 1) = 100 × 0.02 × 0.98^(99) = 0.2707

Thus;

P(X < 2) = 0.1326 + 0.2707

P(X < 2) = 0.4033

P(X ≥ 2) = 1 - 0.4033

P(X ≥ 2) = 0.5967

hey! so 1 (25) out of 4 (100) is 25 so your answer is 25%. it's like quarters!

sas (side angle side)

aa (angle angle)

sss(side side side)

sas find two sides with an angle in between

aa is finding two angles and the third will add up to 180

sss find all sides

step-by-step explanation: