Quadrilateral ABCD is transformed according to the rule (x, y)-> (X + 4, y + 6) to create A'B'C'D'. A The lengths of ABCD are twice the corresponding side lengths of A'B'C'D'
B The angle measures of ABCD are equal to corresponding angle measures of A'B'C'D'
C The side lengths of A'B'C'D' are 4 units longer than ABCD
D The angle measures of A'B'C'D' are greater than the corresponding angle measures of ABCD

its 4 because 2 times 2 is 4, if you double the number two you get four

345

step-by-step explanation:

answer is because 4×10=40

and 98×4= is 392

40,392

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.