The departure from the average is the difference between the actual amount of rain and the average amount of rain for a given month. The historical average for rainfall in Albuquerque, NM for June, July, and August is shown in the table.

June 0.67 inches
July 1.5 inches
August 1.57 inches

Last June only 0.17 inches of rain fell all month. What is the difference between the average rainfall and the actual rainfall for last June? Answer with decimals.

The departure from the average rainfall last July was -0.36 inches. How much rain fell last July? Answer with decimals.

How much rain would have to fall in August so that the total amount of rain equals the average rainfall for these three months? Answer with decimals.

What would the departure from the average be in August in that situation? Answer with decimals.

The actual rainfall for last June is 0.5

1.14 is the amount of rain that fell last July.

2.43 is how much rain would have to fall for August to match the three months average

0.86 is the departure from the average in August

Step-by-step explanation:

1. 0.67-0.17 = 0.5

2. 1.5-0.36 = 1.14

Step-by-step explanation:

a) 0.5 inches. The difference between the average rainfall and the actual rainfall for last June is 0.67-0.17=0.50 inches.

b) 1.14 inches. Because the departure from the average was negative, the actual rainfall was 0.36 inches less than the average rainfall. Thus, 1.5-0.36=1.14 inches was the actual rainfall last July.

c) 2.43 inches. The average rainfall for these three months is 0.67+1.5+1.57=3.74 inches. Last June it rained 0.17 inches and last July it rained 1.14 inches. So, it would need to have rained 3.74-0.17-1.14=2.43 inches last August so that the total amount of rain equaled the average rainfall for these three months.  

0.86 inches. The departure from the average would then be 0.86 inches since 2.43-1.57=0.86 inches.

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then, the surface area of the sphere shown in the image is: 256π sq. units!

step-by-step explanation:

the lateral surface area of a sphere is 2πrh where h=2r.

then:

surface area = 4πr^2.

in this case, r=8 units ⇒ surface area = 4π(8 units)^2. = 256π sq. units!

then, the surface area of the sphere shown in the image is: 256π sq. units!

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step-by-step explanation: