PLS HELP! Let f(x) = ex. Explain how the function would change with a shift to the right by 2, and up by 4 and a vertical stretch of 3, reflected about the x axis.

3 is greater then both of those numbers

0.02

step-by-step explanation:

time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a