A company offers a nut mixture with 4 peanuts for every 3 almonds. The company changes the mixture to have 8 peanuts for every 3 almonds, but the number of nuts per container does not change. How many nuts are in the smallest possible container?

77 nuts

Step-by-step explanation:

From the above question:

We have ratio

Peanuts : Almonds

The original mixture is given as:

A company offers a nut mixture with 4 peanuts for every 3 almonds.

4 : 3

The sum of the proportion = 7

Hence, there are 7 nuts in the container

The new mixture

The company changes the mixture to have 8 peanuts for every 3 almonds,

8 : 3

Sum of the proportion = 11

We are told : the number of nuts per container does not change.

How many nuts are in the smallest possible container?

To solve this, we use the Lowest Common Multiple principle

We find the L. C. M of 7 and 11

Multiples of 7:

7, 14, 21, 28, 35, 42, 49, 56, 63, 70, 77, 84, 91

Multiples of 11:

11, 22, 33, 44, 55, 66, 77, 88, 99

Therefore,

LCM(7, 11) = 77

Therefore, the number of nuts in the smallest possible container is 77 nuts

the forst and 3rd

step-by-step explanation:

v = 1/3 a^2h

step-by-step explanation:

if the height is 57.7cm and the height of the slant edge is 18.2cm, then the volume is 1/3 a^2h.