Determine the sum of the exterior angles in a convex 50-gon. (G.10)(1 point)

The sum of the exterior angles in a convex 50-gon polygon is 360° ⇒ A

Step-by-step explanation:

The formula of the sum of the interior angles of any polygon is ∑ = (n - 2) × 180°, where, n is the number of the sides or the angles of the polygonThe sum of the measures of the interior angle and the exterior angle at a vertex of the polygon is 180°The sum of the exterior angles of any polygon (n-gon) is 360°

In the question

∵ The polygon has 50 sides

→ By using the 3rd rule above

∵ The sum of the exterior angles of any polygon (n-gon) is 360°

∴ The sum of the exterior angles in a convex 50-gon polygon is 360°

Here are the answers to the ones that i could see.

The difference is 5,100m?