Um could you just explain how you got the answer so i can do the rest by myself?? ❤︎❤︎ In APQR, mZP = (4x – 14)", mZQ = (5x + 6)°, and
mZR = (x - 2)°. Find mZR.

x = 19

m<R = 17°

Step-by-step explanation:

PQR is a triangle and the sum of interior angles in a triangle is equal to 180°

m<P + m<Q + m<R = 180°

4x - 14 + 5x + 6 + x - 2 = 180° add like terms

10x - 10 = 180 add 10 from both sides

10x = 190 divide both sides by 10

x = 19

angle R is x - 2 so if we replace x with the value we found

m<R = 19 - 2 = 17°

since the airplane is moving with constant speed then the distance travelled can be calculated by x=u*t

in km/h would be:

x=640*3.5=2.240 km

in m/s would be:

u=640 km/h= 640.000 m/h =640.000/ 3600 m/s =177.8 m/s

t= 3.5 h= 3.5 * 3600 s=12.600 s

then x=u*t= 177.8*12.600= 2.240.280 m

step-by-step explanation: