The half-life of Palladium-100 is 4 days. After 20 days a sample of Palladium-100 has been reduced to a mass of 5 mg.
What was the initial mass (in mg) of the sample?
What is the mass (in mg) 4 weeks after the start?
You may enter the exact value or round to 4 decimal places

A = (Ao)(0.5^(t/t1.2))

1 = (Ao)(0.5^(20/4)) = Ao(0.03125)

Ao = 1/0.03125 = 32mg

5 weeks = 5(7) = 35 days

A = 32(0.5^(35/4)) = 32(0.0232) = 0.074mg

Step-by-step explanation:

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204