What is an equation of the line that passes through the point (8,-4) and is parallel to the line x-4y=12?

x - 4y =12 / -x

-4y = 12 - x // -4

y = -3  1/4 *x

a = 1/4

f(8) = -4

-4 = a*8 + b

-4 = 2 + b / -2

b = -6

so

y = 1/4 *a -6

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

0.50 , 0.75

step-by-step explanation: