U Question 9
10 pts
Solve this system of equations using substitution algebraically. Check your answer using
substitution.
3x + 4y = 36
y= x+8

x = 4/7

y = 60/7

Step-by-step explanation:

3x + 4y = 36

y = x + 8

Substitute the second equation into the first since it already has the y isolated for you:

3x + 4(x + 8) = 36

3x + 4x + 32 = 36

7x = 4

x = 4/7

Take the answer you got from the equation above and plug that into the second equation:

y = 4/7 + 8

y = 60/7

To check just LS/RS both equations:

3(4/7) + 4(60/7) = 36

12/7 = 240/7 = 36

252/7 = 36

36 = 36

LS = RS

60/7 = 4/7 + 8

60/7 = 60/7

LS = RS

3< x< 5

step-by-step explanation:

|x - 4| < 1

there are two solutions, one positive and one negative.   remember to flip the inequality when taking the negative solution

x-4 < 1       x-4 > -1

add 4 to each side

x-4+4 < 1+4       x-4+4 > -1+4

x< 5                 x> 3

3< x< 5

i only know the sequence of arithmetic it adds the first is 5+4 then it goes up as it adds to then it is 9+5 then 14+6 then to 20+7 and so on. 5,9,14,20,27,35.

step-by-step explanation: