Write the first trigonometric function in terms of the second for θ in the given quadrant.. sec θ, sin θ; θ in quadrant i

We have sec  = 1/cos

Then we also have  cos^2 = 1 – sin^2

Also we have cos = sqrt (1 – sin^2)

Substitute the derived cosine function to sec then we have

Sec = 1/(sqrt(1-sin^2)

square root of 36/6 = 2.449489743

square root of 16/6 = 1.632993162

square root of 6 = 2.449489743

the answer is square root of 16/6 because the square root of 36/6 is the same answer as square root of 6 = 2.449489743

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step-by-step explanation: