X The temperature, C, in degrees Celsius recorded by a city park's weather station between midnight and 7:00 a. m. could be represented as a linear function of the number of hours after midnight, t. The temperature at 1:30 a. m. was – 4.2°C and was -8.6°C at 7:00 a. m. Which equation could be used to represent this function? (1 point) O C (t) = -0.8t – 4.2 OC (t) = -1.25t - 8.6 OC (t) = -0.8t - 3 OC (t) = -1.25t - 4.2

C(t) = -0.8t - 3

Step-by-step explanation:

We are told that the temperature at 1:30 a.m. was – 4.2°C and was -8.6°C at 7:00 a.m.

Thus, difference in temperature is;

ΔT = -8.6°C - (-4.2°C)

ΔT = -8.6°C + 4.2°C

ΔT = -4.4°C

Now, number of hours between 1:30 a.m and 7:00 a.m is 5.5 hours.

Thus, average temperature per hour is;

-4.4/5.5 = -0.8°C/h

Now, since C is represented as a linear function of the number of hours after midnight, t.

Then the linear function is -0.8t + x = C(t)

Let's find x.

After 1.5 hours, we have -4.2°C. Thus;

-0.8t + x = -4.2

-0.8(1.5) + x = - 4.2

-1.2 + x = -4.2

x = -4.2 + 1.2

x = -3

Thus, the linear relationship is now;

C(t) = -0.8t - 3

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.

a)(x-2)^2+(y-1)^2=9

step-by-step explanation:

(picture explains)