Suppose 2a-3b = -23. Given that a and b are consecutive integers and a

a = 20 and b = 21

Step-by-step explanation:

Given:

2a-3b = -23

a and b are consecutive

Find:

a and b

Computation:

a = b - 1

So,

2a-3b = -23

2(b-1)-3b = -23

2b - 2 - 3b = -23

-b = -21

b = 21

So

a = b - 1

a = 21-1

a = 20

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation: