3(5x + 2) = -5(3x - 5) + 3x

Distribute 3 in 5x+2 and -5 in 3x-5

Multiplying 2 negatives will be positive (Same goes to dividing 2 negatives.)

Move the x term to the same side and constant term to the same side.

(Whenever you move to another side, change the sign/operator to opposite. From plus to minus and from multiply to divide.)

Thus, the answer is 19/27

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.