Layla opened a savings account and deposited 700.00 as principal the account earns 8%interest compounded annually what is the balance after 6 years

The balance after 6 years is $1110.812026

Step-by-step explanation:

The rule of the compound interest is A = P, where

∵ Layla opened a savings account and deposited $700.00 as principal.

∴ P = 700

∵ The account earns 8% interest compounded annually

∴ r = 8% = 8 ÷ 100 = 0.08

∴ n = 1 ⇒ compounded annually

∵ The time is 6 years

∴ t = 6

→ Substitute these values in the rule above

∵ A = 700

∴ A = 700

∴ A = 1110.812026

∴ The balance after 6 years is $1110.812026

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answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204