Joshua drove his car a distance of 431.8 miles, and it required 10.4 gallons of gasoline (petrol). How many liters of fuel will it take to go 100 kilometers?

6 liters of gasoline

Step-by-step explanation:

Since, 1 km = 0.6214 miles

Therefore, 100 km = 0.6214 × 100 = 62.14 miles

∵ For 431.8 miles of driving Joshua required amount of gasoline = 10.4 gallons

∴ For 1 mile of driving gasoline required = gallons

∴ Gasoline required to drive 62.14 miles = gallons

                                                                   = 1.4967

                                                                   ≈ 1.5 gallons

∵ 1 gallon of gasoline = 3.8 liters

∴ 1.5 gallons of gasoline = 3.8×1.5

                                        = 5.7

                                        ≈ 6 liters

answer: ur v dumb

step-by-step explanation:

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.