. Vacation Days If the average number of vacation days for a selection of various countries has a mean of 29.4 days and a standard deviation of 8.6, find the z scores for the average number of vacation days in each of these countries.

For Canada = -0.3953

For Italy = 1.46511

For USA = -1.9069

Step-by-step explanation:

Given:

Mean μ = 29.4 days

Standard deviation σ = 8.6

Missing Data

For

Canada = 26 days

Italy = 42 days

USA = 13 days

Find:

Z scores

Computation:

Z scores = [X-μ]/σ

For Canada

Z scores = [26-29.4]/8.6

Z scores = -0.3953

For Italy

Z scores = [42-29.4]/8.6

Z scores = 1.46511

For USA

Z scores = [13-29.4]/8.6

Z scores = -1.9069

answer: a

step-by-step explanation:

if xy ~ yz therefore xy would be the same length as yz

answer: none of these answers are correct only the second half is

step-by-step explanation: